/[escript]/trunk/doc/examples/cookbook/example01a.py
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Contents of /trunk/doc/examples/cookbook/example01a.py

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First pass of updating copyright notices
1
2 from __future__ import print_function
3 ##############################################################################
4 #
5 # Copyright (c) 2009-2012 by University of Queensland
6 # http://www.uq.edu.au
7 #
8 # Primary Business: Queensland, Australia
9 # Licensed under the Open Software License version 3.0
10 # http://www.opensource.org/licenses/osl-3.0.php
11 #
12 # Development until 2012 by Earth Systems Science Computational Center (ESSCC)
13 # Development since 2012 by School of Earth Sciences
14 #
15 ##############################################################################
16
17 __copyright__="""Copyright (c) 2009-2012 by University of Queensland
18 http://www.uq.edu.au
19 Primary Business: Queensland, Australia"""
20 __license__="""Licensed under the Open Software License version 3.0
21 http://www.opensource.org/licenses/osl-3.0.php"""
22 __url__="https://launchpad.net/escript-finley"
23
24 """
25 Author: Antony Hallam antony.hallam@uqconnect.edu.au
26 """
27 ############################################################FILE HEADER
28 # example01a.py
29 # Model temperature diffusion between two granite blocks of unequal
30 # initial temperature. Solve for total energy in the system.
31
32 #######################################################EXTERNAL MODULES
33 # To solve the problem it is necessary to import the modules we require.
34 from esys.escript import * # This imports everything from the escript library
35 from esys.escript.unitsSI import *
36 from esys.escript.linearPDEs import LinearPDE # This defines LinearPDE as LinearPDE
37 from esys.finley import Rectangle # This imports the rectangle domain function
38
39 #################################################ESTABLISHING VARIABLES
40 #Domain related.
41 mx = 500*m #meters - model length
42 my = 100*m #meters - model width
43 ndx = 100 # mesh steps in x direction
44 ndy = 1 # mesh steps in y direction - one dimension means one element
45 boundloc = mx/2 # location of boundary between the two blocks
46 #PDE related
47 rho = 2750. *kg/m**3 #kg/m{3} density of iron
48 cp = 790.*J/(kg*K) # J/Kg.K thermal capacity
49 rhocp = rho*cp
50 kappa = 2.2*W/m/K # watts/m.Kthermal conductivity
51 qH=0 * J/(sec*m**3) # J/(sec.m{3}) no heat source
52 T1=20 * Celsius # initial temperature at Block 1
53 T2=2273. * Celsius # base temperature at Block 2
54
55
56 ################################################ESTABLISHING PARAMETERS
57 t=0 * day # our start time, usually zero
58 tend=50 * yr # - time to end simulation
59 outputs = 200 # number of time steps required.
60 h=(tend-t)/outputs #size of time step
61 #user warning statement
62 print("Expected Number of time outputs is: ", (tend-t)/h)
63 i=0 #loop counter
64 #the folder to put our outputs in, leave blank "" for script path
65 save_path= os.path.join("data","example01")
66 #ensure the dir exists
67 mkDir(save_path, os.path.join(save_path,"tempT"))
68
69 ####################################################DOMAIN CONSTRUCTION
70 blocks = Rectangle(l0=mx,l1=my,n0=ndx, n1=ndy)
71
72 ###############################################ESCRIPT PDE CONSTRUCTION
73 #... open PDE and set coefficients ...
74 mypde=LinearPDE(blocks)
75 mypde.setSymmetryOn()
76 A=zeros((2,2))
77 A[0,0]=kappa
78 mypde.setValue(A=A,D=rhocp/h)
79 # ... set initial temperature ....
80 x=Solution(blocks).getX()
81 T= T1*whereNegative(x[0]-boundloc)+T2*(1-whereNegative(x[0]-boundloc))
82
83 ########################################################START ITERATION
84 while t<tend:
85 i+=1
86 t+=h
87 mypde.setValue(Y=qH+rhocp/h*T)
88 T=mypde.getSolution()
89 totE=integrate(rhocp*T)
90 print("time step %s at t=%e days completed. total energy = %e."%(i,t/day,totE))

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