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1 ksteube 1811
2     %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
3 lgraham 1701 %
4 jfenwick 2548 % Copyright (c) 2003-2009 by University of Queensland
5 ksteube 1811 % Earth Systems Science Computational Center (ESSCC)
6     % http://www.uq.edu.au/esscc
7 lgraham 1701 %
8 ksteube 1811 % Primary Business: Queensland, Australia
9     % Licensed under the Open Software License version 3.0
10     % http://www.opensource.org/licenses/osl-3.0.php
11 lgraham 1701 %
12 ksteube 1811 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
13 lgraham 1701
14 ksteube 1811
15 lgraham 1701 \section{Rayleigh-Taylor Instability}
16     \label{LEVELSET CHAP}
17    
18 lgraham 2191 In this section we will implement the Level Set Method in Escript for tracking the interface between two fluids for Computational Fluid Dynamics (CFD). The method is tested with a Rayleigh-Taylor Instability problem, which is an instability of the interface between two fluids with differing densities. \\
19 lgraham 1701 Normally in Earth science problems two or more fluids in a system with different properties are of interest. For example, lava dome growth in volcanology, with the contrast of the two mediums as being lava and air. The interface between the two mediums is often referred to as a free surface (free boundary value problem); the problem arises due to the large differences in densities between the lava and air, with their ratio being around 2000, and so the interface between the two fluids move with respect to each other.
20     %and so the lava with the much higher density is able to move independently with respect to the air, and the interface between the two fluids is not constrained.
21     There are a number of numerical techniques to define and track the free surfaces. One of these methods, which is conceptually the simplest, is to construct a Lagrangian grid which moves with the fluid, and so it tracks the free surface. The limitation of this method is that it cannot track surfaces that break apart or intersect. Another limitation is that the elements in the grid can become severely distorted, resulting in numerical instability. The Arbitrary Lagrangian-Eulerian (ALE) method for CFD in moving domains is used to overcome this problem by remeshing, but there is an overhead in computational time, and it results in a loss of accuracy due to the process of mapping the state variables every remesh by interpolation.
22    
23 lgraham 1973 There is a technique to overcome these limitations called the Level Set Method, for tracking interfaces between two fluids. The advantages of the method is that CFD can be performed on a fixed Cartesian mesh, and therefore problems with remeshing can be avoided. The field equations for calculating variables such as velocity and pressure are solved on the the same mesh. The Level Set Method is based upon the implicit representation of the interface by a continuous function. The function takes the form as a signed distance function, $\phi(x)$, of the interface in a Eulerian coordinate system. For example, the zero isocontour of the unit circle $\phi(x)=x^2 + y^2 -1$ is the set of all points where $\phi(x)=0$. Refer to Figure \ref{UNITCIRCLE}.
24 lgraham 1701 %
25     \begin{figure}
26     \center
27 jfenwick 2335 \scalebox{0.8}{\includegraphics{figures/unitcircle}}
28 lgraham 1701 \caption{Implicit representation of the curve $x^2 + y^2 = 1$.}
29     \label{UNITCIRCLE}
30     \end{figure}
31     %
32 lgraham 1973 The implicit representation can be used to define the interior and exterior of a fluid region. Since the isocontour at $\phi(x)=0$ has been defined as the interface, a point in the domain can be determined if its inside or outside of the interface, by looking at the local sign of $\phi(x)$. For example, a point is inside the interface when $\phi(x)<0$, and outside the interface when $\phi(x)>0$. Parameters values such as density and viscosity can then be defined for two different mediums, depending on which side of the interface they are located.
33 lgraham 1701
34 lgraham 1973
35     \subsection{Calculation of the Displacement of the Interface}
36    
37     The displacement of the interface at the zero isocontour of $\phi(x)$ is calculated each time-step by using the velocity field. This is achieved my solving the advection equation:
38     %
39 lgraham 1701 \begin{equation}
40     \frac{\partial \phi}{\partial t} + \vec{v} \cdot \nabla \phi = 0,
41     \label{ADVECTION}
42     \end{equation}
43 lgraham 1973 %
44 lgraham 2115 where $\vec{v}$ is the velocity field. The advection equation is solved using a mid-point, which is a two step procedure:
45 lgraham 1701
46     Firstly, $\phi^{1/2}$ is calculated solving:
47 lgraham 1973 %
48 lgraham 1701 \begin{equation}
49     \frac{\phi^{1/2} - \phi^{-}}{dt/2} + \vec{v} \cdot \nabla \phi^{-} = 0.
50     \label{MIDPOINT FIST}
51     \end{equation}
52 lgraham 1973 %
53 lgraham 1701 Secondly, using $\phi^{1/2}$, $\phi^{+}$ is calculated solving:
54 lgraham 1973 %
55 lgraham 1701 \begin{equation}
56     \frac{\phi^{+} - \phi^{-}}{dt} + \vec{v} \cdot \nabla \phi^{1/2} = 0.
57     \label{MIDPOINT SECOND}
58     \end{equation}
59 lgraham 1973 %
60 lgraham 2115 This procedure works provided that the discretization of the left-hand side of Equations (\ref{MIDPOINT FIST}) and (\ref{MIDPOINT SECOND}) is a lumped mass matrix. For more details on the mid-point procedure see reference \cite{BOURGOUIN2006}. In certain situations the mid-point procedure has been shown to produce artifacts in the numerical solutions. A more robust procedure is to use the Taylor-Galerkin scheme with the presence of diffusion, which gives more stable solutions. The expression is derived by either inserting Equation (\ref{MIDPOINT FIST}) into Equation (\ref{MIDPOINT SECOND}), or by expanding $\phi$ into a Taylor series:
61 lgraham 1973 %
62 lgraham 1701 \begin{equation}
63     \phi^{+} \simeq \phi^{-} + dt\frac{\partial \phi^{-}}{\partial t} + \frac{dt^2}{2}\frac{\partial^{2}\phi^{-}}{\partial t^{2}},
64     \label{TAYLOR EXPANSION}
65     \end{equation}
66 lgraham 1973 %
67 lgraham 1701 by inserting
68 lgraham 1973 %
69 lgraham 1701 \begin{equation}
70     \frac{\partial \phi^{-}}{\partial t} = - \vec{v} \cdot \nabla \phi^{-},
71     \label{INSERT ADVECTION}
72     \end{equation}
73 lgraham 1973 %
74 lgraham 1701 and
75 lgraham 1973 %
76 lgraham 1701 \begin{equation}
77     \frac{\partial^{2} \phi^{-}}{\partial t^{2}} = \frac{\partial}{\partial t}(-\vec{v} \cdot \nabla \phi^{-}) = \vec{v}\cdot \nabla (\vec{v}\cdot \nabla \phi^{-}),
78     \label{SECOND ORDER}
79     \end{equation}
80 lgraham 1973 %
81     into Equation (\ref{TAYLOR EXPANSION})
82     %
83 lgraham 1701 \begin{equation}
84     \phi^{+} = \phi^{-} - dt\vec{v}\cdot \nabla \phi^{-} + \frac{dt^2}{2}\vec{v}\cdot \nabla (\vec{v}\cdot \nabla \phi^{-}).
85     \label{TAYLOR GALERKIN}
86     \end{equation}
87    
88 lgraham 1973
89 lgraham 2191 %\subsection{Governing Equations for Fluid Flow}
90 lgraham 1973
91 lgraham 2191 %The fluid dynamics is governed by the Stokes equations. In geophysical problems the velocity of fluids are low; that is, the inertial forces are small compared with the viscous forces, therefore the inertial terms in the Navier-Stokes equations can be ignored. For a body force $f$ the governing equations are given by:
92 lgraham 1973 %
93 lgraham 2191 %\begin{equation}
94     %\nabla \cdot (\eta(\nabla \vec{v} + \nabla^{T} \vec{v})) - \nabla p = -f,
95     %\label{GENERAL NAVIER STOKES}
96     %\end{equation}
97 lgraham 1973 %
98 lgraham 2193 %with the incompressibility condition
99 lgraham 1973 %
100 lgraham 2191 %\begin{equation}
101     %\nabla \cdot \vec{v} = 0.
102     %\label{INCOMPRESSIBILITY}
103     %\end{equation}
104 lgraham 1973 %
105 lgraham 2191 %where $p$, $\eta$ and $f$ are the pressure, viscosity and body forces, respectively.
106     %Alternatively, the Stokes equations can be represented in Einstein summation tensor notation (compact notation):
107 lgraham 1973 %
108 lgraham 2191 %\begin{equation}
109     %-(\eta(v\hackscore{i,j} + v\hackscore{j,i})),\hackscore{j} - p,\hackscore{i} = f\hackscore{i},
110     %\label{GENERAL NAVIER STOKES COM}
111     %\end{equation}
112 lgraham 1973 %
113 lgraham 2193 %with the incompressibility condition
114 lgraham 1973 %
115 lgraham 2191 %\begin{equation}
116     %-v\hackscore{i,i} = 0.
117     %\label{INCOMPRESSIBILITY COM}
118     %\end{equation}
119 lgraham 1973 %
120 lgraham 2191 %The subscript comma $i$ denotes the derivative of the function with respect to $x\hackscore{i}$. A linear relationship between the deviatoric stress $\sigma^{'}\hackscore{ij}$ and the stretching $D\hackscore{ij} = \frac{1}{2}(v\hackscore{i,j} + v\hackscore{j,i})$ is defined as \cite{GROSS2006}:
121 lgraham 1973 %
122 lgraham 2191 %\begin{equation}
123     %\sigma^{'}\hackscore{ij} = 2\eta D^{'}\hackscore{ij},
124     %\label{STRESS}
125     %\end{equation}
126 lgraham 1973 %
127 lgraham 2193 %where the deviatoric stretching $D^{'}\hackscore{ij}$ is defined as
128 lgraham 1973 %
129 lgraham 2191 %\begin{equation}
130     %D^{'}\hackscore{ij} = D^{'}\hackscore{ij} - \frac{1}{3}D\hackscore{kk}\delta\hackscore{ij}.
131     %\label{DEVIATORIC STRETCHING}
132     %\end{equation}
133 lgraham 1973 %
134 lgraham 2191 %where $\delta\hackscore{ij}$ is the Kronecker $\delta$-symbol, which is a matrix with ones for its diagonal entries ($i = j$) and zeros for the remaining entries ($i \neq j$). The body force $f$ in Equation (\ref{GENERAL NAVIER STOKES COM}) is the gravity acting in the $x\hackscore{3}$ direction and is given as $f = -g \rho \delta\hackscore{i3}$.
135     %The Stokes equations is a saddle point problem, and can be solved using a Uzawa scheme. A class called StokesProblemCartesian in Escript can be used to solve for velocity and pressure.
136     %In order to keep numerical stability, the time-step size needs to be below a certain value, known as the Courant number. The Courant number is defined as:
137 lgraham 1973 %
138 lgraham 2191 %\begin{equation}
139     %C = \frac{v \delta t}{h}.
140     %\label{COURANT}
141     %\end{equation}
142 lgraham 1973 %
143 lgraham 2191 %where $\delta t$, $v$, and $h$ are the time-step, velocity, and the width of an element in the mesh, respectively. The velocity $v$ may be chosen as the maximum velocity in the domain. In this problem the Courant number is taken to be 0.4 \cite{BOURGOUIN2006}.
144 lgraham 1701
145    
146 lgraham 1973 \subsection{Reinitialization of Interface}
147    
148 lgraham 2115 As the computation of the distance function progresses, it becomes distorted, and so it needs to be updated in order to stay regular \cite{SUSSMAN1994}. This process is known as the reinitialization procedure. The aim is to iteratively find a solution to the reinitialization equation:
149 lgraham 1973 %
150 lgraham 1701 \begin{equation}
151 lgraham 2115 \frac{\partial \psi}{\partial \tau} + sign(\phi)(1 - \nabla \psi) = 0.
152 lgraham 1701 \label{REINITIALISATION}
153     \end{equation}
154 lgraham 1973 %
155 lgraham 2115 where $\psi$ shares the same level set with $\phi$, $\tau$ is pseudo time, and $sign(\phi)$ is the smoothed sign function. This equation is solved to meet the definition of the level set function, $\lvert \nabla \psi \rvert = 1$; the normalization condition. Equation (\ref{REINITIALISATION}) can be rewritten in similar form to the advection equation:
156     %
157     \begin{equation}
158     \frac{\partial \psi}{\partial \tau} + \vec{w} \cdot \nabla \psi = sign(\phi),
159     \label{REINITIALISATION2}
160     \end{equation}
161     %
162     where
163     %
164     \begin{equation}
165     \vec{w} = sign(\phi)\frac{\nabla \psi}{|\nabla \psi|}.
166     \label{REINITIALISATION3}
167     \end{equation}
168     %
169     $\vec{w}$ is the characteristic velocity pointing outward from the free surface. Equation (\ref{REINITIALISATION2}) can be solved by a similar technique to what was used in the advection step; either by the mid-point technique \cite{BOURGOUIN2006} or the Taylor-Galerkin procedure. For the mid-point technique, the reinitialization technique algorithm is:
170 lgraham 1701
171 lgraham 2115 1. Calculate
172     %
173     \begin{equation}
174     \vec{w} = sign(\phi)\frac{\nabla \psi}{|\nabla \psi|},
175     \label{REINITIAL MIDPOINT1}
176     \end{equation}
177     %
178 lgraham 1973
179 lgraham 2115 2. Calculate $\psi^{1/2}$ solving
180     %
181     \begin{equation}
182     \frac{\psi^{1/2} - \psi^{-}}{d\tau/2} + \vec{w} \cdot \nabla \psi^{-}= sign(\phi),
183     \label{REINITIAL MIDPOINT2}
184     \end{equation}
185     %
186    
187     3. using $\psi^{1/2}$, calculate $\psi^{+}$ solving
188     %
189     \begin{equation}
190     \frac{\psi^{+} - \psi^{-}}{d\tau} + \vec{w} \cdot \nabla \psi^{1/2}= sign(\phi),
191     \label{REINITIAL MIDPOINT3}
192     \end{equation}
193     %
194    
195     4. if the convergence criterion has not been met, go back to step 2. Convergence is declared if
196     %
197     \begin{equation}
198     ||\nabla \psi \hackscore{\infty}| - 1| < \epsilon \hackscore{\psi}.
199     \label{REINITIAL CONVERGE}
200     \end{equation}
201     %
202 lgraham 2193 where $\epsilon \hackscore{\psi}$ is the convergence tolerance. Normally, the reinitialization procedure is performed every third time-step of solving the Stokes equation.
203 lgraham 2115
204     The mid-point technique works provided that the left-hand side of Equations (\ref{REINITIAL MIDPOINT2}) and (\ref{REINITIAL MIDPOINT3}) is a lumped mass matrix. Alternatively, for a one-step procedure, the reinitialization equation can be given by:
205     %
206     \begin{equation}
207     \psi^{+} = \psi^{-} - \tau \vec{w} \cdot \nabla \psi^{-} + \frac{d \tau^{2}}{2} \vec{w} \cdot \nabla(\vec{w} \cdot \nabla \psi^{-}).
208     \label{REINITIAL ONESTEP}
209     \end{equation}
210     %
211     The accuracy of $\phi$ is only needed within the transition zone; and so it can be calculated in a narrow band between the interface of the fluids.
212     %
213     \begin{figure}
214     \center
215 jfenwick 2335 \scalebox{0.5}{\includegraphics{figures/LevelSetFlowChart}}
216 lgraham 2193 \caption{Flow chart of Level Set Method procedure \cite{LIN2005}.}
217 lgraham 2115 \label{LEVELSET FLOWCHART}
218     \end{figure}
219     %
220     When the distance function, $\phi$, is calculated, the physical parameters, density and viscosity, are updated using the sign of $\phi$. The jump in material properties between two fluids, such as air and water can be extreme, and so the transition of the properties from one medium to another is smoothed. The region of the interface is assumed to be of finite thickness of $\alpha h$, where $h$ is the size of the elements in the computational mesh and $\alpha$ is a smoothing parameter. The parameters are updated by the following expression:
221     %
222     \begin{equation}
223     P =
224     \left \{ \begin{array}{l}
225     P\hackscore{1} \hspace{5cm} where \ \ \psi < - \alpha h \\
226     P\hackscore{2} \hspace{5cm} where \ \ \psi > \alpha h \\
227     (P\hackscore{2} - P\hackscore{1}) \psi/2\alpha h + (P\hackscore{1} + P\hackscore{2})/2 \ \ \ \ \ \ where \ \ |\psi| < \alpha h.
228     \end{array}
229     \right.
230     \label{UPDATE PARAMETERS}
231     \end{equation}
232     %
233     where the subscripts $1$ and $2$ denote the different fluids. The procedure of the level set calculation is shown in Figure \ref{LEVELSET FLOWCHART}.
234     Further work is needed in the reinitialization procedure, as it has been shown that it is prone to mass loss and inconsistent positioning of the interface \cite{SUCKALE2008}.
235    
236 lgraham 1973 \subsection{Benchmark Problem}
237    
238 lgraham 2128 The Rayleigh-Taylor instability problem is used as a benchmark to validate CFD implementations \cite{VANKEKEN1997}. Figure \ref{RT2DSETUP} shows the setup of the problem. A rectangular domain with two different fluids is considered, with the greater density fluid on the top and the lighter density fluid on the bottom. The viscosities of the two fluids are equal (isoviscous). An initial perturbation is given to the interface of $\phi=0.02cos(\frac{\pi x}{\lambda}) + 0.2$. The aspect ratio $\lambda = L/H = 0.9142$ is chosen such that it gives the greatest disturbance of the fluids. The fluid properties is chosen such that the compositional Rayleigh number is equal to one:
239 lgraham 1973 %
240 lgraham 2128 \begin{equation}
241     R\hackscore{b} = \frac{\Delta \rho H^{3}}{\kappa \eta} = 1.
242     \label{RAYLEIGH NUMBER}
243     \end{equation}
244     %
245     where $\Delta \rho$ is the difference in density between the two fluids, $\eta$ is the viscosity and $\kappa$ is the thermal diffusivity; arbitrarily taken equal to 1 for a ``non thermal'' case.
246     %
247     %
248 lgraham 1701 \begin{figure}
249     \center
250 jfenwick 2335 \scalebox{0.7}{\includegraphics{figures/RT2Dsetup}}
251 lgraham 2120 \caption{Parameters, initial interface and boundary conditions for the Rayleigh-Taylor instability problem. The interface is defined as $\phi=0.02cos(\frac{\pi x}{\lambda}) + 0.2$. The fluids have been assigned different densities and equal viscosity (isoviscous) \cite{BOURGOUIN2006}.}
252 lgraham 1701 \label{RT2DSETUP}
253     \end{figure}
254 lgraham 2128 %
255     %
256 lgraham 2193 The following PYTHON code is for the Rayleigh-Taylor instability problem, which is available in the example directory as 'RT2D.py'. This script uses the 'StokesProblemCartesian' class for solving the Stokes equation, along with the incompressibility condition. A class called 'LevelSet' is also used, which performs the advection and reinitialization procedures to track the movement of the interface of the fluids. The details and use of these classes are described in Chapter \ref{MODELS CHAPTER} (Models Chapter).
257 lgraham 1701
258 jfenwick 2738 The script starts off by importing the necessary classes. The physical properties of the two fluids are defined, such as density and viscosity.
259     Acceleration due to gravity is taken as 10.0 $ms^{-2}$.
260     Solver settings are set for solving the Stokes problem, with the number of time-steps, solver tolerance, maximum solver iterations,
261     and the option to use the Uzawa scheme or not; the default solver is the PCG solver. A regular mesh is defined with 200$\times$200 elements.
262     Level set parameters are set for the reinitialization procedure, such as the convergence tolerance, number of
263     reinitialization steps, the frequency of the reinitialization, for example, every third time-step, and the smoothing
264     parameter to smooth the physical properties across the interface.
265     A no-slip boundary condition is set for the top and bottom of the domain, while on the left and right-hand sides
266     there is a slip condition.
267     The initial interface between the two fluids is defined as in Figure \ref{RT2DSETUP}. Instances of the StokesProblemCartesian and LevelSet class are created.
268     The iteration throughout the time-steps involves the update of the physical parameters of the fluids; the initialization of
269     the boundary conditions, viscosity, and body forces; the solving of the Stokes problem for velocity and pressure; then the
270     level set procedure.
271     The output of the level set function, velocity and pressure is saved to file.
272     The time-step size is selected based on the Courant condition.
273     Due to the number of elements in the computational mesh, the simulation may take a long time to complete on a desktop computer,
274     so it is preferable to run it on the super computer.
275     At present, the fine mesh is required to capture the details of the fluid motion and for numerical stability.
276 lgraham 2128 %
277 lgraham 2115 \begin{python}
278    
279 lgraham 2120 from esys.escript import *
280     import esys.finley
281     from esys.escript.models import StokesProblemCartesian
282     from esys.finley import finley
283 lgraham 2128 from esys.finley import Rectangle
284 lgraham 2120 from LevelSet import *
285 lgraham 2115
286 lgraham 2120 #physical properties
287     rho1 = 1000 #fluid density on bottom
288     rho2 = 1010 #fluid density on top
289     eta1 = 100.0 #fluid viscosity on bottom
290     eta2 = 100.0 #fluid viscosity on top
291     g=10.0
292    
293     #solver settings
294     dt = 0.001
295     t_step = 0
296     t_step_end = 2000
297     TOL = 1.0e-5
298     max_iter=400
299     verbose=True
300     useUzawa=True
301    
302     #define mesh
303     l0=0.9142
304     l1=1.0
305 lgraham 2128 n0=200
306     n1=200
307 lgraham 2120
308 lgraham 2128 mesh=Rectangle(l0=l0, l1=l1, order=2, n0=n0, n1=n1)
309 lgraham 2120 #get mesh dimensions
310     numDim = mesh.getDim()
311     #get element size
312     h = Lsup(mesh.getSize())
313    
314     #level set parameters
315     tolerance = 1.0e-6
316     reinit_max = 30
317     reinit_each = 3
318     alpha = 1
319     smooth = alpha*h
320    
321     #boundary conditions
322     x = mesh.getX()
323     #left + bottom + right + top
324 lgraham 2193 b_c = whereZero(x[0])*[1.0,0.0] + whereZero(x[1])*[1.0,1.0] + whereZero(x[0]-l0)*[1.0,0.0] \
325     + whereZero(x[1]-l1)*[1.0,1.0]
326 lgraham 2120
327     velocity = Vector(0.0, ContinuousFunction(mesh))
328     pressure = Scalar(0.0, ContinuousFunction(mesh))
329     Y = Vector(0.0,Function(mesh))
330    
331     #define initial interface between fluids
332     xx = mesh.getX()[0]
333     yy = mesh.getX()[1]
334     func = Scalar(0.0, ContinuousFunction(mesh))
335     h_interface = Scalar(0.0, ContinuousFunction(mesh))
336     h_interface = h_interface + (0.02*cos(math.pi*xx/l0) + 0.2)
337     func = yy - h_interface
338     func_new = func.interpolate(ReducedSolution(mesh))
339    
340 lgraham 2128 #Stokes Cartesian
341 lgraham 2120 solution=StokesProblemCartesian(mesh,debug=True)
342     solution.setTolerance(TOL)
343     solution.setSubProblemTolerance(TOL**2)
344    
345     #level set
346     levelset = LevelSet(mesh, func_new, reinit_max, reinit_each, tolerance, smooth)
347    
348     while t_step <= t_step_end:
349     #update density and viscosity
350     rho = levelset.update_parameter(rho1, rho2)
351     eta = levelset.update_parameter(eta1, eta2)
352    
353 lgraham 2128 #get velocity and pressure of fluid
354 lgraham 2120 Y[1] = -rho*g
355     solution.initialize(fixed_u_mask=b_c,eta=eta,f=Y)
356 lgraham 2193 velocity,pressure=solution.solve(velocity,pressure,max_iter=max_iter,verbose=verbose, \
357     useUzawa=useUzawa)
358 lgraham 2120
359     #update the interface
360     func = levelset.update_phi(velocity, dt, t_step)
361    
362     print "##########################################################"
363     print "time step:", t_step, " completed with dt:", dt
364     print "Velocity: min =", inf(velocity), "max =", Lsup(velocity)
365     print "##########################################################"
366    
367     #save interface, velocity and pressure
368     saveVTK("phi2D.%2.4i.vtu"%t_step,interface=func,velocity=velocity,pressure=pressure)
369 lgraham 2128 #Courant condition
370 lgraham 2120 dt = 0.4*Lsup(mesh.getSize())/Lsup(velocity)
371     t_step += 1
372    
373 lgraham 2115 \end{python}
374 lgraham 2128 %
375     %
376     The results from the simulation can be viewed by visualization software such as \textit{visIt}. If the software is installed, it can be opened by simply executing the following command:
377     %
378     \begin{python}
379     visit
380     \end{python}
381     %
382     In the visIt main window, vtk/vtu files can be opened from the File menu; contours and vectors can then be displayed by selecting them from the Plots menu and pressing the Draw button. A movie of the simulation can be watched by pressing the Play button. The graphics are displayed in the Vis window. For more information on \textit{visIt} see the website \cite{VisIt}.
383    
384     The simulation output is shown in Figures \ref{RT2D OUTPUT1} and \ref{RT2D OUTPUT1} showing the progression of the interface of the two fluids. A diapir can be seen rising on the left-hand side of the domain, and then later on, a second one rises on the right-hand side.
385     \begin{figure}
386     \center
387 jfenwick 2335 \subfigure[t=300]{\label{RT OUTPUT300}\includegraphics[scale=0.252]{figures/RT2D200by200t300}}
388     \subfigure[t=600]{\label{RT OUTPUT600}\includegraphics[scale=0.252]{figures/RT2D200by200t600}}
389     \subfigure[t=900]{\label{RT OUTPUT900}\includegraphics[scale=0.252]{figures/RT2D200by200t900}}
390     \subfigure[t=1200]{\label{RT OUTPUT1200}\includegraphics[scale=0.252]{figures/RT2D200by200t1200}}
391 lgraham 2193 \caption{Simulation output of Rayleigh-Taylor instability, showing the movement of the interface of the fluids. The contour line represents the interface between the two fluids; the zero contour of the Level Set function. Velocity vectors are displayed showing the flow field. Computational mesh used was 200$\times$200 elements.}
392 lgraham 2128 \label{RT2D OUTPUT1}
393     \end{figure}
394     %
395     \begin{figure}
396     \center
397 jfenwick 2335 \subfigure[t=1500]{\label{RT OUTPUT1500}\includegraphics[scale=0.252]{figures/RT2D200by200t1500}}
398     \subfigure[t=1800]{\label{RT OUTPUT1800}\includegraphics[scale=0.252]{figures/RT2D200by200t1800}}
399 lgraham 2128 \caption{Simulation output of Rayleigh-Taylor instability.}
400     \label{RT2D OUTPUT2}
401     \end{figure}
402     %
403     %
404     %The Level Set Method can be applied to many areas of science, for example simulating subduction zones in geophysics, motion of bubbles, and flame propagation. Its also used in image processing. However, the Level Set Method does have limitations. The level set function can still become irregular after reinitialisation, leading to artifacts in the simulations, requiring more thought into the implementation of the reinitialisation step.
405     %

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