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######################################################## |
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# |
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# Copyright (c) 2003-2008 by University of Queensland |
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# Earth Systems Science Computational Center (ESSCC) |
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# http://www.uq.edu.au/esscc |
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# |
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ksteube |
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# Primary Business: Queensland, Australia |
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# Licensed under the Open Software License version 3.0 |
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# http://www.opensource.org/licenses/osl-3.0.php |
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# |
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######################################################## |
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|
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__copyright__="""Copyright (c) 2003-2008 by University of Queensland |
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Earth Systems Science Computational Center (ESSCC) |
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http://www.uq.edu.au/esscc |
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Primary Business: Queensland, Australia""" |
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__license__="""Licensed under the Open Software License version 3.0 |
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http://www.opensource.org/licenses/osl-3.0.php""" |
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__url__="http://www.uq.edu.au/esscc/escript-finley" |
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""" |
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Some models for flow |
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@var __author__: name of author |
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@var __copyright__: copyrights |
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@var __license__: licence agreement |
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@var __url__: url entry point on documentation |
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@var __version__: version |
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@var __date__: date of the version |
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""" |
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__author__="Lutz Gross, l.gross@uq.edu.au" |
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from escript import * |
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import util |
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from linearPDEs import LinearPDE, LinearPDESystem, LinearSinglePDE |
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from pdetools import HomogeneousSaddlePointProblem,Projector, ArithmeticTuple, PCG, NegativeNorm |
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class DarcyFlow(object): |
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""" |
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solves the problem |
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M{u_i+k_{ij}*p_{,j} = g_i} |
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M{u_{i,i} = f} |
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|
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where M{p} represents the pressure and M{u} the Darcy flux. M{k} represents the permeability, |
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@note: The problem is solved in a least squares formulation. |
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""" |
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|
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def __init__(self, domain,useReduced=False): |
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""" |
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initializes the Darcy flux problem |
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@param domain: domain of the problem |
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@type domain: L{Domain} |
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""" |
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self.domain=domain |
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self.__pde_v=LinearPDESystem(domain) |
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if useReduced: self.__pde_v.setReducedOrderOn() |
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self.__pde_v.setSymmetryOn() |
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self.__pde_v.setValue(D=util.kronecker(domain), A=util.outer(util.kronecker(domain),util.kronecker(domain))) |
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self.__pde_p=LinearSinglePDE(domain) |
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self.__pde_p.setSymmetryOn() |
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if useReduced: self.__pde_p.setReducedOrderOn() |
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self.__f=Scalar(0,self.__pde_v.getFunctionSpaceForCoefficient("X")) |
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self.__g=Vector(0,self.__pde_v.getFunctionSpaceForCoefficient("Y")) |
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self.__ATOL= None |
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def setValue(self,f=None, g=None, location_of_fixed_pressure=None, location_of_fixed_flux=None, permeability=None): |
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""" |
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assigns values to model parameters |
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|
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@param f: volumetic sources/sinks |
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@type f: scalar value on the domain (e.g. L{Data}) |
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@param g: flux sources/sinks |
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@type g: vector values on the domain (e.g. L{Data}) |
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@param location_of_fixed_pressure: mask for locations where pressure is fixed |
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@type location_of_fixed_pressure: scalar value on the domain (e.g. L{Data}) |
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@param location_of_fixed_flux: mask for locations where flux is fixed. |
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@type location_of_fixed_flux: vector values on the domain (e.g. L{Data}) |
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@param permeability: permeability tensor. If scalar C{s} is given the tensor with |
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C{s} on the main diagonal is used. If vector C{v} is given the tensor with |
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C{v} on the main diagonal is used. |
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@type permeability: scalar, vector or tensor values on the domain (e.g. L{Data}) |
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|
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@note: the values of parameters which are not set by calling C{setValue} are not altered. |
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@note: at any point on the boundary of the domain the pressure (C{location_of_fixed_pressure} >0) |
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or the normal component of the flux (C{location_of_fixed_flux[i]>0} if direction of the normal |
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is along the M{x_i} axis. |
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""" |
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if f !=None: |
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f=util.interpolate(f, self.__pde_v.getFunctionSpaceForCoefficient("X")) |
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if f.isEmpty(): |
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f=Scalar(0,self.__pde_v.getFunctionSpaceForCoefficient("X")) |
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else: |
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if f.getRank()>0: raise ValueError,"illegal rank of f." |
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self.f=f |
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if g !=None: |
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g=util.interpolate(g, self.__pde_p.getFunctionSpaceForCoefficient("Y")) |
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if g.isEmpty(): |
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g=Vector(0,self.__pde_v.getFunctionSpaceForCoefficient("Y")) |
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else: |
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if not g.getShape()==(self.domain.getDim(),): |
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raise ValueError,"illegal shape of g" |
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self.__g=g |
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if location_of_fixed_pressure!=None: self.__pde_p.setValue(q=location_of_fixed_pressure) |
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if location_of_fixed_flux!=None: self.__pde_v.setValue(q=location_of_fixed_flux) |
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if permeability!=None: |
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perm=util.interpolate(permeability,self.__pde_p.getFunctionSpaceForCoefficient("A")) |
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if perm.getRank()==0: |
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perm=perm*util.kronecker(self.domain.getDim()) |
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elif perm.getRank()==1: |
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perm, perm2=Tensor(0.,self.__pde_p.getFunctionSpaceForCoefficient("A")), perm |
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for i in range(self.domain.getDim()): perm[i,i]=perm2[i] |
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elif perm.getRank()==2: |
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pass |
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else: |
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raise ValueError,"illegal rank of permeability." |
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self.__permeability=perm |
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self.__pde_p.setValue(A=util.transposed_tensor_mult(self.__permeability,self.__permeability)) |
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def getFlux(self,p=None, fixed_flux=Data(),tol=1.e-8, show_details=False): |
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""" |
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returns the flux for a given pressure C{p} where the flux is equal to C{fixed_flux} |
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on locations where C{location_of_fixed_flux} is positive (see L{setValue}). |
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Note that C{g} and C{f} are used, see L{setValue}. |
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@param p: pressure. |
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@type p: scalar value on the domain (e.g. L{Data}). |
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@param fixed_flux: flux on the locations of the domain marked be C{location_of_fixed_flux}. |
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@type fixed_flux: vector values on the domain (e.g. L{Data}). |
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@param tol: relative tolerance to be used. |
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@type tol: positive C{float}. |
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@return: flux |
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@rtype: L{Data} |
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@note: the method uses the least squares solution M{u=(I+D^*D)^{-1}(D^*f-g-Qp)} where M{D} is the M{div} operator and M{(Qp)_i=k_{ij}p_{,j}} |
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for the permeability M{k_{ij}} |
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""" |
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self.__pde_v.setTolerance(tol) |
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g=self.__g |
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f=self.__f |
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self.__pde_v.setValue(X=f*util.kronecker(self.domain), r=fixed_flux) |
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if p == None: |
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self.__pde_v.setValue(Y=g) |
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else: |
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self.__pde_v.setValue(Y=g-util.tensor_mult(self.__permeability,util.grad(p))) |
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return self.__pde_v.getSolution(verbose=show_details) |
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def getPressure(self,v=None, fixed_pressure=Data(),tol=1.e-8, show_details=False): |
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caltinay |
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""" |
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returns the pressure for a given flux C{v} where the pressure is equal to C{fixed_pressure} |
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on locations where C{location_of_fixed_pressure} is positive (see L{setValue}). |
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Note that C{g} is used, see L{setValue}. |
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@param v: flux. |
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@type v: vector-valued on the domain (e.g. L{Data}). |
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@param fixed_pressure: pressure on the locations of the domain marked be C{location_of_fixed_pressure}. |
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@type fixed_pressure: vector values on the domain (e.g. L{Data}). |
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@param tol: relative tolerance to be used. |
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@type tol: positive C{float}. |
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@return: pressure |
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@rtype: L{Data} |
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@note: the method uses the least squares solution M{p=(Q^*Q)^{-1}Q^*(g-u)} where and M{(Qp)_i=k_{ij}p_{,j}} |
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for the permeability M{k_{ij}} |
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""" |
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self.__pde_v.setTolerance(tol) |
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g=self.__g |
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self.__pde_p.setValue(r=fixed_pressure) |
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if v == None: |
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self.__pde_p.setValue(X=util.transposed_tensor_mult(self.__permeability,g-v)) |
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else: |
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self.__pde_p.setValue(X=util.transposed_tensor_mult(self.__permeability,g)) |
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return self.__pde_p.getSolution(verbose=show_details) |
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def setTolerance(self,atol=0,rtol=1e-8,p_ref=None,v_ref=None): |
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""" |
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set the tolerance C{ATOL} used to terminate the solution process. It is used |
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M{ATOL = atol + rtol * max( |g-v_ref|, |Qp_ref| )} |
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where M{|f|^2 = integrate(length(f)^2)} and M{(Qp)_i=k_{ij}p_{,j}} for the permeability M{k_{ij}}. If C{v_ref} or C{p_ref} is not present zero is assumed. |
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The iteration is terminated if for the current approximation C{p}, flux C{v=(I+D^*D)^{-1}(D^*f-g-Qp)} and their residual |
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M{r=Q^*(g-Qp-v)} |
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the condition |
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M{<(Q^*Q)^{-1} r,r> <= ATOL} |
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holds. M{D} is the M{div} operator and M{(Qp)_i=k_{ij}p_{,j}} for the permeability M{k_{ij}} |
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@param atol: absolute tolerance for the pressure |
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@type atol: non-negative C{float} |
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@param rtol: relative tolerance for the pressure |
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@type rtol: non-negative C{float} |
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@param p_ref: reference pressure. If not present zero is used. You may use physical arguments to set a resonable value for C{p_ref}, use the |
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L{getPressure} method or use the value from a previous time step. |
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@type p_ref: scalar value on the domain (e.g. L{Data}). |
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@param v_ref: reference velocity. If not present zero is used. You may use physical arguments to set a resonable value for C{v_ref}, use the |
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L{getFlux} method or use the value from a previous time step. |
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@type v_ref: vector-valued on the domain (e.g. L{Data}). |
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@return: used absolute tolerance. |
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@rtype: positive C{float} |
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""" |
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g=self.__g |
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if not v_ref == None: |
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f1=util.integrate(util.length(util.interpolate(g-v_ref,Function(self.domain)))**2) |
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else: |
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f1=util.integrate(util.length(util.interpolate(g))**2) |
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if not p_ref == None: |
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f2=util.integrate(util.length(util.tensor_mult(self.__permeability,util.grad(p_ref)))**2) |
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else: |
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f2=0 |
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self.__ATOL= atol + rtol * util.sqrt(max(f1,f2)) |
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if self.__ATOL<=0: |
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raise ValueError,"Positive tolerance (=%e) is expected."%self.__ATOL |
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return self.__ATOL |
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def getTolerance(self): |
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""" |
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returns the current tolerance. |
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@return: used absolute tolerance. |
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@rtype: positive C{float} |
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""" |
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if self.__ATOL==None: |
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raise ValueError,"no tolerance is defined." |
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return self.__ATOL |
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def solve(self,u0,p0, max_iter=100, verbose=False, show_details=False, sub_rtol=1.e-8): |
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""" |
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solves the problem. |
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The iteration is terminated if the residual norm is less then self.getTolerance(). |
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@param u0: initial guess for the flux. At locations in the domain marked by C{location_of_fixed_flux} the value of C{u0} is kept unchanged. |
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@type u0: vector value on the domain (e.g. L{Data}). |
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@param p0: initial guess for the pressure. At locations in the domain marked by C{location_of_fixed_pressure} the value of C{p0} is kept unchanged. |
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@type p0: scalar value on the domain (e.g. L{Data}). |
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@param sub_rtol: tolerance to be used in the sub iteration. It is recommended that M{sub_rtol<rtol*5.e-3} |
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@type sub_rtol: positive-negative C{float} |
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@param verbose: if set some information on iteration progress are printed |
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@type verbose: C{bool} |
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@param show_details: if set information on the subiteration process are printed. |
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@type show_details: C{bool} |
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@return: flux and pressure |
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@rtype: C{tuple} of L{Data}. |
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@note: The problem is solved as a least squares form |
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M{(I+D^*D)u+Qp=D^*f+g} |
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M{Q^*u+Q^*Qp=Q^*g} |
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|
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where M{D} is the M{div} operator and M{(Qp)_i=k_{ij}p_{,j}} for the permeability M{k_{ij}}. |
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We eliminate the flux form the problem by setting |
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|
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M{u=(I+D^*D)^{-1}(D^*f-g-Qp)} with u=u0 on location_of_fixed_flux |
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caltinay |
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|
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form the first equation. Inserted into the second equation we get |
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caltinay |
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M{Q^*(I-(I+D^*D)^{-1})Qp= Q^*(g-(I+D^*D)^{-1}(D^*f+g))} with p=p0 on location_of_fixed_pressure |
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which is solved using the PCG method (precondition is M{Q^*Q}). In each iteration step |
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PDEs with operator M{I+D^*D} and with M{Q^*Q} needs to be solved using a sub iteration scheme. |
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""" |
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self.verbose=verbose |
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self.show_details= show_details and self.verbose |
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self.__pde_v.setTolerance(sub_rtol) |
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self.__pde_p.setTolerance(sub_rtol) |
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ATOL=self.getTolerance() |
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if self.verbose: print "DarcyFlux: absolute tolerance = %e"%ATOL |
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######################################################################################################################### |
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# |
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# we solve: |
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# |
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# Q^*(I-(I+D^*D)^{-1})Q dp = Q^* (g-u0-Qp0 - (I+D^*D)^{-1} ( D^*(f-Du0)+g-u0-Qp0) ) |
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# |
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# residual is |
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# |
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# r= Q^* (g-u0-Qp0 - (I+D^*D)^{-1} ( D^*(f-Du0)+g-u0-Qp0) - Q dp +(I+D^*D)^{-1})Q dp ) = Q^* (g - Qp - v) |
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# |
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# with v = (I+D^*D)^{-1} (D^*f+g-Qp) including BC |
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# |
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# we use (g - Qp, v) to represent the residual. not that |
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# |
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# dr(dp)=( -Q(dp), dv) with dv = - (I+D^*D)^{-1} Q(dp) |
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# |
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# while the initial residual is |
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# |
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# r0=( g - Qp0, v00) with v00=(I+D^*D)^{-1} (D^*f+g-Qp0) including BC |
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# |
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d0=self.__g-util.tensor_mult(self.__permeability,util.grad(p0)) |
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self.__pde_v.setValue(Y=d0, X=self.__f*util.kronecker(self.domain), r=u0) |
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v00=self.__pde_v.getSolution(verbose=show_details) |
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if self.verbose: print "DarcyFlux: range of initial flux = ",util.inf(v00), util.sup(v00) |
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self.__pde_v.setValue(r=Data()) |
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# start CG |
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r=ArithmeticTuple(d0, v00) |
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p,r=PCG(r,self.__Aprod_PCG,p0,self.__Msolve_PCG,self.__inner_PCG,atol=ATOL, rtol=0.,iter_max=max_iter, verbose=self.verbose) |
304 |
|
|
return r[1],p |
305 |
caltinay |
2169 |
|
306 |
gross |
2208 |
def __Aprod_PCG(self,dp): |
307 |
|
|
if self.show_details: print "DarcyFlux: Applying operator" |
308 |
|
|
# -dr(dp) = (Qdp,du) where du = (I+D^*D)^{-1} (Qdp) |
309 |
|
|
mQdp=util.tensor_mult(self.__permeability,util.grad(dp)) |
310 |
|
|
self.__pde_v.setValue(Y=mQdp,X=Data(), r=Data()) |
311 |
|
|
du=self.__pde_v.getSolution(verbose=self.show_details) |
312 |
|
|
return ArithmeticTuple(mQdp,du) |
313 |
caltinay |
2169 |
|
314 |
gross |
2100 |
def __inner_PCG(self,p,r): |
315 |
gross |
2208 |
a=util.tensor_mult(self.__permeability,util.grad(p)) |
316 |
|
|
f0=util.integrate(util.inner(a,r[0])) |
317 |
|
|
f1=util.integrate(util.inner(a,r[1])) |
318 |
|
|
# print "__inner_PCG:",f0,f1,"->",f0-f1 |
319 |
|
|
return f0-f1 |
320 |
gross |
2100 |
|
321 |
|
|
def __Msolve_PCG(self,r): |
322 |
gross |
2208 |
if self.show_details: print "DarcyFlux: Applying preconditioner" |
323 |
|
|
self.__pde_p.setValue(X=util.transposed_tensor_mult(self.__permeability,r[0]-r[1]), r=Data()) |
324 |
|
|
return self.__pde_p.getSolution(verbose=self.show_details) |
325 |
gross |
2100 |
|
326 |
gross |
1414 |
class StokesProblemCartesian(HomogeneousSaddlePointProblem): |
327 |
|
|
""" |
328 |
gross |
2208 |
solves |
329 |
gross |
1414 |
|
330 |
gross |
2208 |
-(eta*(u_{i,j}+u_{j,i}))_j + p_i = f_i-stress_{ij,j} |
331 |
|
|
u_{i,i}=0 |
332 |
gross |
1414 |
|
333 |
gross |
2208 |
u=0 where fixed_u_mask>0 |
334 |
|
|
eta*(u_{i,j}+u_{j,i})*n_j-p*n_i=surface_stress +stress_{ij}n_j |
335 |
gross |
1414 |
|
336 |
gross |
2208 |
if surface_stress is not given 0 is assumed. |
337 |
gross |
1414 |
|
338 |
gross |
2208 |
typical usage: |
339 |
gross |
1414 |
|
340 |
gross |
2208 |
sp=StokesProblemCartesian(domain) |
341 |
|
|
sp.setTolerance() |
342 |
|
|
sp.initialize(...) |
343 |
|
|
v,p=sp.solve(v0,p0) |
344 |
gross |
1414 |
""" |
345 |
|
|
def __init__(self,domain,**kwargs): |
346 |
gross |
2100 |
""" |
347 |
gross |
2208 |
initialize the Stokes Problem |
348 |
gross |
2100 |
|
349 |
gross |
2208 |
@param domain: domain of the problem. The approximation order needs to be two. |
350 |
gross |
2100 |
@type domain: L{Domain} |
351 |
gross |
2208 |
@warning: The apprximation order needs to be two otherwise you may see oscilations in the pressure. |
352 |
gross |
2100 |
""" |
353 |
gross |
1414 |
HomogeneousSaddlePointProblem.__init__(self,**kwargs) |
354 |
|
|
self.domain=domain |
355 |
|
|
self.vol=util.integrate(1.,Function(self.domain)) |
356 |
|
|
self.__pde_u=LinearPDE(domain,numEquations=self.domain.getDim(),numSolutions=self.domain.getDim()) |
357 |
|
|
self.__pde_u.setSymmetryOn() |
358 |
gross |
2100 |
# self.__pde_u.setSolverMethod(self.__pde_u.DIRECT) |
359 |
|
|
# self.__pde_u.setSolverMethod(preconditioner=LinearPDE.RILU) |
360 |
gross |
2208 |
|
361 |
gross |
1414 |
self.__pde_prec=LinearPDE(domain) |
362 |
|
|
self.__pde_prec.setReducedOrderOn() |
363 |
gross |
2156 |
# self.__pde_prec.setSolverMethod(self.__pde_prec.LUMPING) |
364 |
gross |
1414 |
self.__pde_prec.setSymmetryOn() |
365 |
|
|
|
366 |
|
|
self.__pde_proj=LinearPDE(domain) |
367 |
|
|
self.__pde_proj.setReducedOrderOn() |
368 |
|
|
self.__pde_proj.setSymmetryOn() |
369 |
|
|
self.__pde_proj.setValue(D=1.) |
370 |
|
|
|
371 |
gross |
2100 |
def initialize(self,f=Data(),fixed_u_mask=Data(),eta=1,surface_stress=Data(),stress=Data()): |
372 |
gross |
2208 |
""" |
373 |
|
|
assigns values to the model parameters |
374 |
gross |
2100 |
|
375 |
gross |
2208 |
@param f: external force |
376 |
|
|
@type f: L{Vector} object in L{FunctionSpace} L{Function} or similar |
377 |
|
|
@param fixed_u_mask: mask of locations with fixed velocity. |
378 |
|
|
@type fixed_u_mask: L{Vector} object on L{FunctionSpace} L{Solution} or similar |
379 |
|
|
@param eta: viscosity |
380 |
|
|
@type eta: L{Scalar} object on L{FunctionSpace} L{Function} or similar |
381 |
|
|
@param surface_stress: normal surface stress |
382 |
|
|
@type eta: L{Vector} object on L{FunctionSpace} L{FunctionOnBoundary} or similar |
383 |
|
|
@param stress: initial stress |
384 |
|
|
@type stress: L{Tensor} object on L{FunctionSpace} L{Function} or similar |
385 |
|
|
@note: All values needs to be set. |
386 |
|
|
|
387 |
|
|
""" |
388 |
|
|
self.eta=eta |
389 |
|
|
A =self.__pde_u.createCoefficient("A") |
390 |
|
|
self.__pde_u.setValue(A=Data()) |
391 |
|
|
for i in range(self.domain.getDim()): |
392 |
|
|
for j in range(self.domain.getDim()): |
393 |
|
|
A[i,j,j,i] += 1. |
394 |
|
|
A[i,j,i,j] += 1. |
395 |
|
|
self.__pde_prec.setValue(D=1/self.eta) |
396 |
|
|
self.__pde_u.setValue(A=A*self.eta,q=fixed_u_mask,Y=f,y=surface_stress) |
397 |
|
|
self.__stress=stress |
398 |
gross |
1414 |
|
399 |
gross |
2100 |
def B(self,v): |
400 |
gross |
2208 |
""" |
401 |
|
|
returns div(v) |
402 |
|
|
@rtype: equal to the type of p |
403 |
gross |
1414 |
|
404 |
gross |
2208 |
@note: boundary conditions on p should be zero! |
405 |
|
|
""" |
406 |
|
|
if self.show_details: print "apply divergence:" |
407 |
|
|
self.__pde_proj.setValue(Y=-util.div(v)) |
408 |
|
|
self.__pde_proj.setTolerance(self.getSubProblemTolerance()) |
409 |
|
|
return self.__pde_proj.getSolution(verbose=self.show_details) |
410 |
gross |
2100 |
|
411 |
|
|
def inner_pBv(self,p,Bv): |
412 |
|
|
""" |
413 |
gross |
2208 |
returns inner product of element p and Bv (overwrite) |
414 |
|
|
|
415 |
gross |
2100 |
@type p: equal to the type of p |
416 |
|
|
@type Bv: equal to the type of result of operator B |
417 |
gross |
2208 |
@rtype: C{float} |
418 |
|
|
|
419 |
gross |
2100 |
@rtype: equal to the type of p |
420 |
|
|
""" |
421 |
|
|
s0=util.interpolate(p,Function(self.domain)) |
422 |
|
|
s1=util.interpolate(Bv,Function(self.domain)) |
423 |
gross |
1414 |
return util.integrate(s0*s1) |
424 |
|
|
|
425 |
gross |
2100 |
def inner_p(self,p0,p1): |
426 |
|
|
""" |
427 |
gross |
2208 |
returns inner product of element p0 and p1 (overwrite) |
428 |
|
|
|
429 |
gross |
2100 |
@type p0: equal to the type of p |
430 |
|
|
@type p1: equal to the type of p |
431 |
gross |
2208 |
@rtype: C{float} |
432 |
|
|
|
433 |
gross |
2100 |
@rtype: equal to the type of p |
434 |
|
|
""" |
435 |
|
|
s0=util.interpolate(p0/self.eta,Function(self.domain)) |
436 |
|
|
s1=util.interpolate(p1/self.eta,Function(self.domain)) |
437 |
|
|
return util.integrate(s0*s1) |
438 |
artak |
1550 |
|
439 |
gross |
2100 |
def inner_v(self,v0,v1): |
440 |
|
|
""" |
441 |
gross |
2208 |
returns inner product of two element v0 and v1 (overwrite) |
442 |
|
|
|
443 |
gross |
2100 |
@type v0: equal to the type of v |
444 |
|
|
@type v1: equal to the type of v |
445 |
gross |
2208 |
@rtype: C{float} |
446 |
|
|
|
447 |
gross |
2100 |
@rtype: equal to the type of v |
448 |
|
|
""" |
449 |
gross |
2208 |
gv0=util.grad(v0) |
450 |
|
|
gv1=util.grad(v1) |
451 |
gross |
2100 |
return util.integrate(util.inner(gv0,gv1)) |
452 |
|
|
|
453 |
gross |
1414 |
def solve_A(self,u,p): |
454 |
|
|
""" |
455 |
gross |
2208 |
solves Av=f-Au-B^*p (v=0 on fixed_u_mask) |
456 |
gross |
1414 |
""" |
457 |
gross |
2100 |
if self.show_details: print "solve for velocity:" |
458 |
gross |
1414 |
self.__pde_u.setTolerance(self.getSubProblemTolerance()) |
459 |
gross |
2100 |
if self.__stress.isEmpty(): |
460 |
|
|
self.__pde_u.setValue(X=-2*self.eta*util.symmetric(util.grad(u))+p*util.kronecker(self.domain)) |
461 |
|
|
else: |
462 |
|
|
self.__pde_u.setValue(X=self.__stress-2*self.eta*util.symmetric(util.grad(u))+p*util.kronecker(self.domain)) |
463 |
|
|
out=self.__pde_u.getSolution(verbose=self.show_details) |
464 |
gross |
2208 |
return out |
465 |
gross |
1414 |
|
466 |
|
|
def solve_prec(self,p): |
467 |
gross |
2100 |
if self.show_details: print "apply preconditioner:" |
468 |
gross |
1414 |
self.__pde_prec.setTolerance(self.getSubProblemTolerance()) |
469 |
|
|
self.__pde_prec.setValue(Y=p) |
470 |
|
|
q=self.__pde_prec.getSolution(verbose=self.show_details) |
471 |
artak |
1554 |
return q |